Math, asked by Hbhadouriya2532, 11 months ago

f(x)=mx+c & f(0)=f'(0)=1 ,so find f(2).

Answers

Answered by waqarsd
0

f(x) = mx + c \\  \\ diff \\  \\  {f}^{1} (x) = m \\  \\ given \\  \\ f(0) =  {f}^{1} (0) = 1 \\  \\ m(0) + c = 1 \\  \\ c = 1 \\  \\ also \\  \\ m = 1 \\  \\ therefore \\  \\ f(x) = x + 1 \\  \\ f (2)=2+1=3\\\\

hope it helps

Answered by Needthat
1

f(x) = mx + c \\  \\ diff \\  \\  {f}^{1} (x) = m \\  \\ given \\  \\ f(0) =  {f}^{1} (0) = 1 \\  \\ m(0) + c = 1 \\  \\ c = 1 \\  \\ also \\  \\ m = 1 \\  \\ therefore \\  \\ f(x) = x + 1 \\  \\

hope it helps

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