F(x) = { n + 1 if n is even , n-3 if n is odd
find F if it is surjective or injective ?
please explain your answer !
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Answer:
case 1. F(x)= (n+1), when n= even
F(x) = (2+1)
F(x)= 3
case 2. F(x)= (n-1), when n= odd
F(x)= (3-1)
F(x)= 2
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