Math, asked by triggerAVS705, 1 year ago

f(x)=px+q, p≠0, p q are real numbers. ,Find the zero of the polynomial in give case.

Answers

Answered by 567839
19
f(x)=px+q
px+q=0
px=-q
x=-q/p

Answered by kannarammaheshwari
1

Step-by-step explanation:

answer.

px+q=0

px = -q

x = - q/p

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