f(x)=px+q, p≠0, p q are real numbers. ,Find the zero of the polynomial in give case.
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Answered by
19
f(x)=px+q
px+q=0
px=-q
x=-q/p
px+q=0
px=-q
x=-q/p
Answered by
1
Step-by-step explanation:
answer.
px+q=0
px = -q
x = - q/p
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