Question

f(x) = root of x -3, g(x) = 5 - x, if f(x)=g(x),find x​

Answer 1

$\sqrt (x-3)$ = 5-x

=> x-3 = (5-x)^2

=> x-3 = 25-10x+x^2

=> 28 - 11x +x^2=0

=> x^2 -11x +28=0

=> x^2 -4x-7x +28 =0

=> x(x-4) -7(x-4)=0

=> (x-7)(x-4)=0

therefore, x=7 / x=4