Question

f(x) = sin^2x - cos^2x then the value of f' ( 45 )

Answer 1

Hello user☺☺

We have , f(x) = sin^2x - cos^2x

Putting x = 45° , we get

f' ( 45 ) = Sin^2(45°) - cos^2(45°)

= 1/2 - 1/2

= 0.

Hope this will help☺☺