f(x)=sin x+cos 2x then f(π/4)=? & f(π/6)=?
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Answered by
1
f(pie/4) =1/sqroot2
f(pie/6)=1
f(pie/6)=1
Answered by
1
f(π/4)=sinπ/4 + cosπ/2
=1/√2 + 0
=1/√2
f(π/6)=sinπ/6 + cosπ/3
=1/2 + 1/2
= 1
therefore. f(π/4)=1/√2
f(π/6)=1
=1/√2 + 0
=1/√2
f(π/6)=sinπ/6 + cosπ/3
=1/2 + 1/2
= 1
therefore. f(π/4)=1/√2
f(π/6)=1
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