Question

F(x) =sin x + cos x them find f(π) =

Answer 1

Answer:

here's your answer

Given f(x)=∣cosx−sinx∣

For 0<x<

4

π

,f(x)=cosx−sinx

For

4

π

<x<

2

π

,f(x)=sinx−cosx

On differentiating

For 0<x<

4

π

,f

′

(x)=−sinx−cosx

For

4

π

<x<

2

π

,f

′

(x)=cosx+sinx

⟹f

′

(

3

π

)=cos

3

π

+sin

3

π

=

2

1

+

2

3

=

2

3

+1

I hope it's helpful for you