f(x) = sin[x]+[sin x],0<x<π/2 (where [.] represent greatest integer function ),can also be represented as
Answers
Answered by
1
Step-by-step explanation:
We know that the range of sinx in (0,
2
π
) is in (0,1).
∴[sinx]=0 for x∈(0,
2
π
)
Hence,
I=∫0dx=0+c=c {where c is the constant of integration}
Similar questions