f(x)=sin⁴x+cos⁴x,0<x<πlocal minimun value of given function is
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Step-by-step explanation:
Let f(x)=cos
4
x+sin
4
x
=(cos
2
x)
2
+(sin
2
x)
2
=(cos
2
x+sin
2
x)
2
−2sin
2
xcos
2
x.................[a
2
+b
2
=(a+b)
2
−2ab]
=1−
2
(sin2x)
2
for max value of f(x),sin2x=0
f(x)=1−0=1
for min. value of f(x),sinx=1 or −1
f(x)=1−
2
1
=
2
1
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