Question

f(x)=sinx+cosx, than max. value of x

Answer 1

maximum value of sinx is 1, here x =90
maximum value of cosx is 1, here x =0

If we take x =0=>f (x) = 1
take x =90 then f(x) =1

So take x = 90+0/2=45.

Hence,maximum value of f(x) = sin45+cos45 =1.4

Therefore maximum value of x is 45.

Hope it helps.

Answer 2

hey there !!

=) F(x) = sinx+cosx

=) differentiate wrt x we get

dF/dx = cosx -sinx

◆ for Maxima and minima

=) dF/dx = 0

=) cosx -sinx =0

=) cos x = sinx

=) dividing by cosx

=) tanx = 1

general solution for this eqn is : π/4 ,5π/4
,9π/4 .....

so it's 1st Maxima is at x = π/4

F(π/4) = sinπ/4 + cosπ/4 = 1/√2 +1/√2 = √2

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hope it will help u