Question

F(x): sq root of x ,g(x) : cube root of x, then find value: f(f(x)+g(x))

Answer 1

Given :f(x)=$\sqrt x$, g(x)=$(x)^{\frac{1}{3}$

To find: f [f(x)+g(x)]

Solution:  f [f(x)+g(x)]

               = f[$\sqrt x+(x)^{\frac{1}{3}$]

              As , f(x)=$\sqrt x$

     = $f[\sqrt x+(x)^{\frac{1}{3}]=(\sqrt x+(x)^{\frac{1}{3})^{\frac{1}{2}}$