Question

f(x) = \sqrt{x+ x^{2} }
f'(x) =

Answer 1

Answer:

f'(x) =

$\frac{1}{2 \sqrt{x + {x}^{2} } } \times (1 + 2x)$

$= \frac{(1 + 2x)}{2 \sqrt{x + {x}^{2} } }$

[THANK YOU]