Math, asked by Krystal95, 5 months ago

f(x)= $\sqrt{2x^{2} }+4x-1$

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Answered by daisyDrishti

24

$f(x)=\sqrt{2x^{2} }+4x-1 \\ = 2x + 4x - 1 \\ = 6x - 1$

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