f(x)=
![\sqrt{3 - x} \sqrt{3 - x}](https://tex.z-dn.net/?f=+%5Csqrt%7B3+-+x%7D+)
g(x)=
![\sqrt{2 - x} \sqrt{2 - x}](https://tex.z-dn.net/?f=+%5Csqrt%7B2+-+x%7D+)
then domain of (fog)x=
BestStudentSince2004:
g(x) = ?
Answers
Answered by
1
Answer:
√3-√(2-x)
3-√(2-x)≥0
3≥√(2-x)
square on b. s.
9≥2-x
7≥-x
x≤7
x should be [-7, 2]
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