Question

f(x)=√x-1 + √6-x find the domain ​

Answer 1

Step-by-step explanation:

$f(x) = \sqrt{x - 1} + \sqrt{6 - x} \\ = > the \: square \: root \: must \: always \: be \: greater \: than \: 0 \\ = > x - 1 \geqslant 0 \: \: \: and \: \: \: 6 - x \geqslant 0 \\ = > x \geqslant 1 \: \: \: and \: \: \: x \leqslant 6$

so the domain of function must lie in

x € [1,6]

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