f(x)=[x-1]+[x-2]+[x-3] if 1
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Heya mate here is ur verified answer......
It is given that:- f(x)=[x-1]+[x-2]+[x-3]
To find :- value of f(x) if x=1
SOLUTION......:-
f(x)=[x-1]+[x-2]+[x-3]
f(1)=[1-1]+[1-2]+[1-3]
≈ [0]+[-1]+[-2]
= 0+(-1)+(-2)
=0-1-2
= -1-2
= -3......ANSWER ...
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