Question

f(x) = (x+2)^2 - 2 Find the Table of values

Answer 1

f(x)=x

2

(x−2)

2

f

′

(x)=2x(x−2)

2

+2(x−2).x

2

=2x(x−2)[x−2+x]

=2x(x−2)[2x−2]

=4x(x−2)(x−1).

Now

f

′

(x)>0

4x(x−2)(x−1)>0

Or

x(x−2)(x−1)>0