Question

f(x) =(x+2)²
(a) find f(2) and f(-3)
(b) find x when f(x)= 0​

Answer 1

Step-by-step explanation:

f(x)=x2−3x+1

f(2α)=(2α)2−3(2α)+1=4α2−6α+1

f(2α)=2f(α)

∴4α2−6α+1=2(α2−3α+1)

4α2−6α+1=2α2−bα+2

4α2+1=2α2+2

2α2=1       α=±21

Answer 2

Step-by-step explanation:

Given,

f(x)=(x+2)^2

(a) put x=2 in f(x), we get

f(2)=(2+2)^2

=(2)^2+(2)^2+2.2.2

=4+4+8

= 16 ans

put x=-3 in f(x) , we get

f(-3)=(-3+2)^2

=(-3)^2+(2)^2+2.(-3).2

=9+4-12

=13-12=1 ans

(b) put x=0 in f(x) , we get

f(0)=(0+2)^2

=(0)^2+(2)^2+2.0.2

=0+4+0

=4 ans