Math, asked by mahendrayaduvanshi30, 7 months ago

f(x)=x^2+2x-3 then find the value of f(-1),f(1/3),f(sin x)​

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Answered by venkateshsharma4
1

Answer:

f(-1) = -4

f(-1) = -4f(1/3) = -20/9

f(-1) = -4f(1/3) = -20/9f(sinx) = sin^2x + 2sinx - 3

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hope this will help ☺️☺️

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