Question

f(x) = x^
2 + 2x-5
​

Answer 1

Step-by-step explanation:

${x}^{2} + 2x - 5 \\ \\ by \: quadratic \: formula \\ \\ x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{ - ( - 2) + - \sqrt{ { (- 2)}^{2} - 4(1)( - 5)} }{2 \times 1} \\ \\ x = \frac{2 + - \sqrt{4 + 20} }{2} \\ \\ x = \frac{2(1 + - \sqrt{6} )}{2} \\ \\ \\ \\ x = 1 + \sqrt{6 \: \: \: } \: \: \: \: \: \: or \\ \\ x = 1 - \sqrt{6}$

Answer 2

Answer : - 1-root 24 and - 1+root 24

[tex] {x}^{2} + 2x - 5 \\ solving \: by \: quadratic \: formula - \\ a = 1 \: \: b = 2 \: and \: c = ( - 5) \\ - b \ \sqrt{{b}^{2} - 4ac} \div 2a \\hey \: mate \: do \: add \: a + and \: - sign \: before \: the \: root \: \\ so \: putting \: the \: values \\ - 2 \sqrt{4 - 4( - 5) } \div 2 \\ - 2 \sqrt{24} \div 2 \\ so \: your \: answer \: is \: \\ - 1 + \sqrt{24} \: and \: - 1 - \sqrt{24} [tex]