f(x)=x^2-3x+5 then find f(sin3pi/2)+f(cos3pi/2)
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Answered by
4
sin(3π/2)= 1/2
=> f(1/2) = (1/2)²-3(1/2)+5
=15/4
And,
Cos(3π/2)=-1/2
=>f(-1/2)=27/4
summing up both as required,
=> (15+27)/4
= 42/4
=> f(1/2) = (1/2)²-3(1/2)+5
=15/4
And,
Cos(3π/2)=-1/2
=>f(-1/2)=27/4
summing up both as required,
=> (15+27)/4
= 42/4
santhii:
sin(3pi/2)=-1 so the entire sum is wrong na
correct answer is 8 isn't it?
Answered by
3
Sin 3 pi/2=-1
Thus,f(1)= 1+3+5=9
Cos 3 pi/2=-1/2
Thus,f(1/2)=1/4+3/2+5=27/4..
Hope it helps :)
its wrong
sin 3pi/2=-1 then f(-1)=9,cos3pi/2=0 then f(0)=5 then answer is 9+5=14
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