Question

f(x)=x^2-3x+7 has a critical point at

Answer 1

Answer:

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Answer 2

Answer:

x= 3/2 is the critical point of the function.

given:

Given function is f(x)=x²-3x+7

to Find:

find the critical point of the above function

Step-by-step explanation:

Critical point:

Critical point of any function is that point , where its dy/dx is either zero or it is not defined. This point is called critical because here the behavior of the function immediately changes.

so we will find dy/dx of the given function.

dy/dx = d/dx(x²-3x+7 )

dy/dx = 2x -3

dy/dx = 0

2x-3 = 0

2x = 3

x= 3/2

so x= 3/2 is the critical point for function x²-3x+7 because at x = 3/2 , the value of dy/dx of the function is zero.