Question

f(x) = x^2 -3x, then the points at which f(x)= f'(x) are

correct answer would be marked brainliest​

Answer 1

Step-by-step explanation:

f'(x)=2x-3

put f'(x)=0

2x-3=0

2x=3

x=3/2

When x< 3/2

, then, f(x)>0 and when x> 3/2 , then f(x)<0.

Since the sign changes from positive to negative, so the function has local minima at x= 3/2