f(x)=x^2-5x+4 then find f(b+1)
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Answer:
f(x)=x²-5x+4.
f(b+1)=(b+1)²-5(b+1)+4.
=(b)²+2(b)(1)+(1)²-5b-5+4. (Because (a+b)²=a²+2ab+b² where a=b & b=1 & -×+=-).
=b²+2b+1-5b-5+4.
=b²+2b-5b+1-5+4. (Because by combining like terms to avoid confusion).
=b²-3b+1-1. (Because +×-=- & -×+=- & largest number is important).
=b²-3b. (Because +×-=- so, +1-1 will cancel i.e., it will be zero(0)).
I think this is your answer.
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