f(x)=|x-2| and g(x)= f[f(x)] find g'(x) for x>20
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for 2 x f(x) = x-2
now, g(x)= f[x-2] =f ([x] - 2) we need to define piece wise
1) for 2 x x
2) for 3 x
so g(x)=2 in case 1 and g(x)=1 in case 2 you can sustitute values of x for verification
be brainly
regards genius 1223
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swarnajitpaul72:
wrong answer ... it was a modulus sign
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