f(x)=x^2
With Verification
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Answered by
2
Answer:
f(x)=
f(1)=1*1=1
Step-by-step explanation:
Answered by
1
Answer:
Given f(x)=x2+2 is continuous in [−2,2] and differentiable in (−2,2)
Also f(a)=f(−2)=(−2)2+2=6
f(b)=f(2)=22+2=6
∴f(a)=f(b)=6
∴ Value of f(x) at x=−2 and 2 coincide
∴ According to Rolle's theorem ∃cϵ(a,b) such that
f1(c)=0
∴f1(x)=2x
⇒f1(c)=2c=0
∴c=0ϵ(−2,2).
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