F(x) = x^2 + x is bijecive?
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f: R -> R : f(x) = x^2 + x
x = [ -1 + √(1+4 f) ] /2 or [-1 - √(1+4 f) ] /2
for example : x = 4 from Domain R maps onto f(x) = 20 in range R.
also x = -5 also maps onto f(x) = 20.
So f is not a one to one function. So it is not bijective. Also the Range is a subset of the domain.
x = [ -1 + √(1+4 f) ] /2 or [-1 - √(1+4 f) ] /2
for example : x = 4 from Domain R maps onto f(x) = 20 in range R.
also x = -5 also maps onto f(x) = 20.
So f is not a one to one function. So it is not bijective. Also the Range is a subset of the domain.
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