Question

f(x)=x^3-3x^2+ax-15 is divided by x-3 . find a if remainder is -9

Answer 1

Answer- x-3=0

x=3

p(x)= x^3-3x^2+ax-15=-9

p(3)=(3)^3-3(3)^2+(3)a-15+9=0

=27-27+3a-6=0

=3a=6

a=6/3

a=2