f(x)=x^3-4, find f^-1(x)
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f (x)=x^3-4=0
=x^3=4
=x=1.58
f^-1 (x)
=1.58^-1 (1.58)
=-1.58×1.58
=0
=x^3=4
=x=1.58
f^-1 (x)
=1.58^-1 (1.58)
=-1.58×1.58
=0
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