f(x)=x^3+7x^2+mx+n.
Find m and n
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Answer:
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Question :
Find the values if m and n. If x + 3 is a factor of f(x) = x³ + 7x² + mx + n and f(x) = 35.
Solution :
» x + 3 is a factor of f(x) = x³ + 7x² + mx + n.
→ x + 3 = 0
→ x = - 3
Put value of x in this .. x³ + 7x² + mx + n
→ f(-3) = (-3)³ + 7(-3)² + m(-3) + n
→ 0 = - 27 + 7(9) - 3m + n
→ 0 = - 27 + 63 - 3m + n
→ 0 = 36 - 3m + n
→ 3m - n = 36 _______ (eq 1)
Now..
f(x) = 35
Let x = 0
→ f(0) = (0)³ + 7(0)² + m(0) + n
→ 35 = 0 + 0 + 0 + n
→ n = 35
Put value of n in (eq 1)
→ 3m - 35 = 36
→ 3m = 36 + 35
→ 3m = 71
→ m = 71/3
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m = 71/3 and n = 35
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