F(x) =x^3;g(y)=y-1;h(z)=z+1 find the value of f(g(h(x)))
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Answer:
x^3
Step-by-step explanation:
h(x) = x+1, g(y) = y-1
firstly calculating, g(h(x)) = (x+1)-1 = x
therefore f(g(h(x))) = f(x) = x^3
hope it helps!!!
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