Question

F(x) = x^4 - 3 x² + 4, g(x) = x-2​

Answer 1

f(x) = x4 – 3x2 + 4, g(x) = x – 2 Put g(x) = 0 ⇒ x – 2 = 0 or x = 2 Remainder = f(2) Now, f(2) = (2)4 – 3(2)2 + 4 = 16 – 12 + 4 = 8

Answer 2

Step-by-step explanation:

${x}^{4} - 3 {x}^{2} + 4 \\ \div \\ x - 2 \\ x = 2 \\ {2}^{4} - 3 \times {2}^{2} + 4 \\ 16 - 12 +4 \\ 20 - 12 \\ 8$