Math, asked by avelinteresa, 1 year ago

f(x)=x-4/4-x find domain and range

Answers

Answered by Kamal2002
63

Domain is the set of all possible x values .

So x-4/4-x is only possible if 4-x is not equal to 0 .

Then at x=4 f(x) is not possible .

So domain of f(x) is set of all real numbers except 4.

Now range is the set of all y values possible .

Thus simplifying f(x) we get,

x-4/(-1)(x-4)

= -1

Thus range of f(x) is -1 as that is the only possible y value no matter what x is .


Hope this helps.


avelinteresa: thank u
Kamal2002: ;)
Answered by jhangir789
1

The domain and range of the real function f defined by f(x)= \frac{4-x}{x-4}$  is given by, Domain = \mathbf{R}-\{4\}$, Range = \{-1\}$.

How do you find the domain and range of a given function?

  • To find the domain and range, we simply solve the equation y = f(x) to determine the values of the independent variable x and obtain the domain.
  • To calculate the range of the function, we simply express x as x=g(y) and then find the domain of g(y).

How do you find the range of a function?

Overall, the steps for algebraically finding the range of a function are:

  • Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).
  • Find the domain of g(y), and this will be the range of f(x).
  • If you can't seem to solve for x, then try graphing the function to find the range.

How do you write the domain of a function?

  • Identify the input values.
  • Since there is an even root, exclude any real numbers that result in a negative number in the radicand.
  • Set the radicand greater than or equal to zero and solve for x .
  • The solution(s) are the domain of the function.

According to the question:

Given that: f (x) = \frac{4-x}{x-4}$

We know that f(x) is defined if x-4 \neq 0$

$$\Rightarrow x \neq 4$$

So, the domain of f(x) is = R- {4}

Let f(x) = y = \frac{4-x}{x-4}$

$$\begin{aligned}&\Rightarrow y x-4 y=4-x \\&\Rightarrow y x+x=4 y+4 \\&\Rightarrow x(y+1)=4 y+4 \\&\Rightarrow x=\frac{4(1+y)}{1+y}\end{aligned}$$

If x is real number, then 1+y \neq 0$

$$\Rightarrow y \neq-1$$

Therefore, Range of f(x)=R - {-1 }

Hence, The domain and range of the real function f defined by f(x)= \frac{4-x}{x-4}$  is given by, Domain = \mathbf{R}-\{4\}$, Range = \{-1\}$.

Learn more about  domain and range here,

https://brainly.in/question/3358149?msp_poc_exp=5

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