f(x)=x-4 g(x)=x2 h(x)=3x-5 to show (fog) oh =fo(goh)
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Given:
f(x) = x - 4
g(x) = x²
h(x) = 3x - 5
To prove:
(fog)oh = fo(goh)
OR (fog)oh(x) = fo(goh)(x)
Proof:
Firstly,
(fog)(x) = f[g(x)]
= f(x²)
= x² - 4
Now,
LHS = (fog)oh(x)
= (fog)(3x - 5)
= (3x - 5)² - 4
= 9x² - 30x + 25 - 4
= 9x² - 30x + 21
Secondly,
(goh)(x) = g[h(x)]
= g(3x-5)
= (3x - 5)²
= 9x² - 30x + 25
Now,
RHS = fo(goh)(x)
= f(9x² - 30x + 25)
= 9x² - 30x + 25 - 4
= 9x² - 30x + 21
Since,
LHS = RHS
Hence proved.
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