*f(x) = | x – 5 | is*
1️⃣ continuous at point 5 2️⃣ continuous for all real numbers 3️⃣ discontinuous at point 5
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We know that the greatest integer function is discontinuous at integer values. For a value of x just smaller than 5, the greatest integer smaller than it is 4. So,
limx→5−[x]=4
f(x=5)=[5]=5
For a value of x just bigger than 5, the greatest integer smaller than it is 5. So,
limx→5+[x]=5
Since limx→5−f(x)=f(5), the function is not left continuous.
Since limx→5+f(x)=f(5), the function is right continuous.
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Answer:
Option-A
Continuous At Point 5
Step-by-step explanation:
GIVEN- f(x) = | x – 5 |
TO FIND- continuous at which point
CONCEPT - f(x)= LHS= RHS that means it wil be continuous
SOLUTION - x – 5= 0
x= 5
At a point -
f(x)= 5
f(x)= | x – 5 |
f(x)= |5-5|
f(x)= 0
this is first equation
at LHS-
f(x)= LHS= lim- f(5) = | x – 5 |
f(x)= |5-5|
f(x)= 0
second equation
at RHS-
f(x)= RHS= lim- f(5) = | x – 5 |
f(x)= |5-5|
f(x)= 0
third equation
from equation First second and third we get that -
f(x)= LHS= RHS= 5
#SPJ3
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