Question

f ( x )= x cube minus 6 X square + 11 x minus 6 g( x )= X + 2​

Answer 1

Answer:

Step-by-step explanation:Given (x^3)-6(x^2)+11x-6=0

x^3-3x^2-3x^2+11x-6=0

x^2(x-3)-(3x^2-11x+6)=0

x^2(x-3)-(3x^2-9x-2x+6)=0

x^2(x-3)-(3x(x-3)-2(x-3))=0

x^2(x-3)-[(x-3)(3x-2)]=0

(x-3)(x^2-3x+2)=0

(x-3)(x^2-2x-x+2)=0

(x-3)(x(x-2)-1(x-2))=0

(x-3)(x-2)(x-1)=0

Answer 2

Answer:

X - 2 is not a factor of x cube minus 6 X square + 11 x minus 6