Question

f(x)=x/x^2+1 and g(x)=2x-1 then find fog(x)

Answer 1

Answer:

Step-by-step explanation:If f(x)=2x-1 and g(x)=2/x-1, how do you find (fog) (-1) + (f-1 o g-1) (√2)?

Let’s proceed by steps

First, we’ll evaluate

g(−1)=2−1−1=−2−1=−3

Then

f(−3)=2(−3)−1=−6−1=−7

So

f∘g(−1)=−7

Now

g(x)=y⇔y=2x−1⇔2x=y+1⇔x2=1y+1⇔x=2y+1

g−1(x)=2x+1

In particular

g−1(2–√)=22√+1=2(2√−1(2√+1)(2√−1)=2(2√−1)2−1=2(2–√−1)

Similarily,

f(x)=y⇔y=2x−1⇔2x=y+1⇔x=y+12

f−1(x)=x+12

So

f−1∘g−1(2–√)=f−1(2(2–√−1))=2(2√−1)+12=2–√−1+12=2–√−12

And, finally

f∘g(−1)+f−1∘g−1(2–√)=−7+2–√−12=2–√−152

Answer 2

Hi Friend !!!

Here is ur answer !!!

f(x) = x/x² +1 = 1/x +1

g(x) = 2x-1

fog(x) = f(g(x))

= f(2x-1)

= 1/2x-1 +1

= 1+2x-1/2x-1

= 2x/2x-1

Hope it helps u :-)