Math, asked by afsarahe06, 19 days ago

f(x)=x2+2kx2−2x+h
when f(x) is divided by (x+2) the remainder is 9 and when f(x) is divided by (x-3) the remainder is 49. find the value of k and h.​

Answers

Answered by tanveerchoudhary954
0

Answer:

Let f(x)=2x

3

+3x

2

−kx+5

By remainder theorem, when f(x) is divided by (x−2)

x−2=0,⇒x=2

the remainder =f(2)

=2(2)

3

+3(2)

2

−k(2)+5

=16+12−2k+5

=33−2k

According to question

33−2k=7

⇒2k=26

⇒k=13

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