f(x)=x2+2kx2−2x+h
when f(x) is divided by (x+2) the remainder is 9 and when f(x) is divided by (x-3) the remainder is 49. find the value of k and h.
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Answer:
Let f(x)=2x
3
+3x
2
−kx+5
By remainder theorem, when f(x) is divided by (x−2)
x−2=0,⇒x=2
the remainder =f(2)
=2(2)
3
+3(2)
2
−k(2)+5
=16+12−2k+5
=33−2k
According to question
33−2k=7
⇒2k=26
⇒k=13
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