Question

f(x)=x2+2x+1 ; g(x)=x+2

Answer 1

f(x) = x^2 + 2x + 1

g(x) = x + 2

=> x = -2

=> f(-2) = (-2)^2 + 2(-2) + 1

= 4 - 4 + 1

= 1

Answer 2

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$\large\mathcal\red{solution}$

$f(x) = x {}^{2} + 2x + 1 \\ g(x) = x + 2 \\ now \: applying \: the \: remainder \: theorem \: \\ x + 2 = 0 \\ x - 2 \\ therefore \: the \: remainder \: is \: when \: \\ ... f(x) \: is \: divided \: by \: g(x).... \\ f( - 2) = ( - 2) {}^{2} + 2( - 2)1 \\ = 4 - 4 + 1 \\ = 1$

$\underline{\large\mathcal\red{hope\: this \: helps \:you......}}$