Question

f(x)={x2+3, x<2
5x+7, x>2 },then find. f(0)

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given

f ( x ) = { x² + 3 , x < 2 ; 5x + 7 , x > 2 }

f ( 0 ) = { 0² + 3 }

f ( 0 ) = { 0 + 3 }

f ( 0 ) = { 3 }

f ( 0 ) = { 5 ( 0 ) + 7 }

f ( 0 ) = { 0 + 7 }

f ( 0 ) = { 7 }

So f ( 0 ) = { 3 ; 7 }