Question

f(x)= x²-3x+1/x-1. find f(-2)+f(1/3)​

Answer 1

Step-by-step explanation:

f(-2)=(-2)^2-3×-2+1/-2-1

=4+6+1/ -3

= 4+-7/3

=4×3-7/3

= 12-7/3

f(-2) =5/3. --(1)

f(1/3) = (1/3)^2 -3×1/3+1/1/3-1

= 1/9 -1+1/1-3/3

= 1/9-0/-2/3

=1/9-3/2

=2-27/18

=25/18. ---(2)

f(-2)+ f(1/3)

by putting value of 1st and 2nd equations-

5/3+ 25/18

5×6 +25/18

30+25/18

55/18 this is the required Ans.

hope it will help you

Answer 2

Answer:

Answer :- f(-2) + f(1/3) = $\frac{-23}{6}$ .

Step-by-step explanation:

Given :- $f(x) = \frac{x^2 - 3x +1 }{x-1 }$

To find :- f(-2) + f($\frac{1}{3}$)

Solution :-

Step 1) Given , $f(x) = \frac{x^2-3x+1}{x-1}$ ---- (1)

Step 2) f(-2) = $\frac{(-2)^2-(3*-2)+1 }{-2-1} \\\frac{4+6+1}{-3}\\ \frac{-11}{3}$---- (2)

Step 3)  f($\frac{1}{3}$)

$\frac{(1/3)^2-(1/3*3)+1}{1/3-1} \\\frac{-1}{6}$--- (3)

Step 4)

f(-2) + f(1/3) = $\frac{-11}{3} +\frac{-1}{6} \\\frac{(-11*6)+(-1*3)}{18} \\\frac{-66-3}{18}\\\\\frac{-69}{18} \\\frac{-23}{6}$

Step 5)

Answer :- f(-2) + f(1/3) = $\frac{-23}{6}$ .

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