Question

F(x) = x²-5x+4 then f(b+1)​

Answer 1

Answer:

b(b-3)

Step-by-step explanation:

F(x) =

${x}^{2} - 5x + 4$

then f(b+1)

=

$(b + 1)^{2} - 5(b + 1) + 4$

${b}^{2} + {1}^{2} + 2(b)(1) - 5(b + 1) + 4$

${b}^{2} + 1 + 2b - 5b - 5 + 4$

${b}^{2} - 3b - 1 + 1$

${b}^{2} - 3b$

$b(b - 3)$

Answer 2

F(x) = x^2- 5x+4
= x^2-(4+1)x+4
= x^2-4x-x+4
= x(x-4)-1(x-4)
= (x-1)(x-4)

Therefore,
F(b+1) = (b+1-1)(b+1-4)
=b(b-3) [Ans]