f (x) =x2 , g(x) = 3x + 2 (i) (f+g) (x)
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Answer:
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Step-by-step explanation:
f(x)=3x−2
(g.f)
−1
=x−2
Let y=x−2⇒x=2+y⇒y
−1
=2+x
((g.f)
−1
)
−1
=2+x
⇒g.f=2+x
⇒g(f(x))=x+2
⇒g(3x−2)=3x−2+2=3x
Let 3x−2=t⇒x=
3
t+2
g(t)=
3
t+2
+2
g(t)=
3
t+8
∴g(x)=
3
x+8
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