f(x) = x3 – 3x2 – 2x + 8
a)Use the factor theorem to show (x-2) is a factor of f(x).
b. Using algebraic division, divide (x-2) with f(x).
C. With your answer found in (b), factorize f(x).
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Answer:
Here, f(x)=x3–2x2–9x+18
So, x–2=0⇒x=2
Thus, remainder =f(2)
=(2)3–2(2)2–9(2)+18
=8–8–18+18
=0
Therefore, (x–2) is a factor of f(x).
Now, performing division of polynomial f(x) by (x–2) we have
Thus, x3–2x2–9x+18=(x–2)(x2–9)=(x–2)(x+3)(x–3)
Step-by-step explanation:
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