Question

f(x)=x³+4x²-3x+10 and g(x) =x+4 find the remainder​

Answer 1

Step-by-step explanation:

(x) = x3 + 4x2 – 3x + 10, g(x) = x + 4 Put g(x) = 0 ⇒ x + 4 = 0 or x = -4

Remainder = f(-4)

Now, f(-4) = (-4)3 + 4(-4)2 – 3(-4) + 10 = -64 + 64 + 12 + 10 = 22

hope it helps :)$\huge \pink{~} \red {τ} \green {α} \blue {v} \orange {v} \pink {u} \red {♡}$

Answer 2

(x) = x3 + 4x2 - 3x + 10, g(x) = x + 4 Put g(x) = 0 x + 4 = 0 or x = -4

Remainder = f(-4)

Now, f(-4)= (-4)3 + 4(-4)2 - 3(-4) + 10 = -64 + 64 + 12 + 10 = 22