f(x)=x³-4x²+x+6, g(x)=x-2,Use the Factor Theorem to determine whether g(x) is factor of f(x) in each cases.
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21
yes g(x) is a factor of p(x)
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Answered by
32
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Factor Theorem :
Let p(x) be a polynomial of
degree one or more than 1 and
a is a real number .Then
i ) x-a , will be a factor of p(x) if
p(a) = 0 conversely ,
ii ) If x - a is a factor of p(x) ,
then p(a) = 0
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Here ,
F(x) = x³ - 4x² + x + 6 ,
g(x) = x - 2
g(x) = 0
=> x - 2 = 0
=> x = 2
Therefore ,
Zero of g(x) is 2 ,
Now ,
p(2) = 2³ - 4(2)² +2 + 6
= 8 - 16 + 2 + 6
= 16 - 16
= 0
Therefore ,
By Factor theorem ,
g(x ) is a factor of f(x).
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