Question

f(x)=x³-6x²+2x-4, g(x)=1-2x​

Answer 1

Answer:

Step-by-step explanation:

f(x) = x3 – 6x2 + 2x – 4, g(x) = 1 – 2x Put g(x) = 0 ⇒ 1 – 2x = 0 or x =  1 2 12 Remainder = f( 1 2 12)  Now,  f( 1 2 12) = ( 1 2 12)3 – 6( 1 2 12)2 + 2( 1 2 12) – 4  = 1 + 1 8 18 – 4 – 3 2 32  =  − 35 8  607137/x-3-6x-2-2x-4-g-x-1-2x