Question

f(x)=x³ +kx-4x-12 ..... If f(x-2)= 0 then, k =?​

Answer 1

Answer:

6

Step-by-step explanation:

firstly, x-2=0

x=0+2

x=2

so,

f(x)=x^3+kx-4x-12

f(2)=(2)^3+k(2)-4(2)-12

=8+2k-8-12=0

=2k-12=0

=2k=12

=k=12/2

=k=6