Question

f(x)=x⁴,find f'(x) for it.

Answer 1

x=x4
x=x*x*x*x
x=4 sq
x=4/2
x=2

Answer 2

answer : 4x³

explanation : it is given that, function f(x) = x⁴

we have to find f'(x) of given function.

f'(x) represents first derivative of f(x).

i.e., f'(x) = d[f(x)]/dx

= d(x⁴)/dx

we know, if any function, y = g(x)ⁿ, where n is integral number. then, dy/dx = d[g(x)ⁿ]/dx = ng(x)ⁿ-¹ × d[g(x)]/dx

similarly, first derivative of given function, f'(x) = d[x⁴]/dx

= $4x^{(4-1)}\times\frac{dx}{dx}$

= 4x³

hence, f'(x) = 4x³ [ ans]