f(x)=xsinx find f'(x)
Answers
Answered by
1
Step-by-step explanation:
xcosx+sinx(1)=xcosx+sinx
Answered by
0
- if y=f(x) g (x)
- then differentiation w.r.t.x
- dy/dx=f(x) dg(x)/dx+g(x)df(x)/dx
- Now Use This
- y=x.sinx
- dy/dx=x.d (sinx)/dx+sinx.dx/dx
- =x.cosx+sinx
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